Impulse response

So far circuits have been driven by a DC source, an AC source and an exponential source. If we can find the current of a circuit generated by a Dirac delta function or impulse voltage source δ, then the convolution integral can be used to find the current to any given voltage source!

Example Impulse Response[edit | edit source]

The current is found by taking the derivative of the current found due to a DC voltage source! Say the goal is to find the δ current of a series LR circuit ... so that in the future the convolution integral can be used to find the current given any arbitrary source.

Choose a DC source of 1 volt (the real Vs then can scale off this). The particular homogeneous solution (steady state) is 0. The homogeneous solution to the non-homogeneous equation has the form:

Assume the current initially in the inductor is zero. The initial voltage is going to be 1 and is going to be across the inductor (since no current is flowing):


If the current in the inductor is initially zero, then:

Which implies that:
So the response to a DC voltage source turning on at t=0 to one volt (called the unit response μ) is:

Taking the derivative of this, get the impulse (δ) current is:

Now the current due to any arbitrary VS(t) can be found using the convolution integral:

Don't think iδ as current. It is really . VS(τ) turns into a multiplier.

LRC Example[edit | edit source]

Find the time domain expression for io given that Is = cos(t + π/2)μ(t) amp.

Earlier the step response for this problem was found:

The impulse response is going to be the derivative of this:


The Mupad code to solve the integral (substituting x for τ) is:

f := exp(-(t-x)) *sin(t-x) *(1 + cos(x));<br>S := int(f,x = 0..t)

Finding the integration constant[edit | edit source]

This implies:

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